tag:blogger.com,1999:blog-9377477453558795442024-03-05T20:53:03.826-03:00Curta BiologiaA Biologia é uma ciência que encanta as pessoas apaixonadas pela vida e pela natureza.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.comBlogger102125tag:blogger.com,1999:blog-937747745355879544.post-37841599595925594892017-09-22T13:50:00.001-03:002017-09-22T13:52:49.448-03:00TESTE DE BIOLOGIA ON-LINE<span style="font-size: large;">Link do teste on-line de biologia</span><br />
<span style="font-size: large;"><br /></span>
<span style="font-size: large;"><a href="https://docs.google.com/forms/d/1G7sBzJokktoD34Epj7zWh7SQL5UfMwomM0JERjbcmTw/edit">https://docs.google.com/forms/d/1G7sBzJokktoD34Epj7zWh7SQL5UfMwomM0JERjbcmTw/edit</a></span><br />
<br />
coloquem este link no grupo das respectivas salas para os que faltaram a aula possa realizar a atividade.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-67530857686541159702017-09-12T12:40:00.001-03:002017-09-22T13:56:26.690-03:00LINKS DOS DOCUMENTÁRIOS ASSISTIR ESTES DOCUMENTÁRIOS PARA A REALIZAÇÃO DAS AVALIAÇÕES.<br />
LINK DO DOCUMENTÁRIO CONSTRUINDO O PLANETA TERRA<br />
<br />
<div class="separator" style="clear: both; text-align: center;">
<iframe allowfullscreen="" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/MPATtHrY1AM/0.jpg" frameborder="0" height="266" src="https://www.youtube.com/embed/MPATtHrY1AM?feature=player_embedded" width="320"></iframe></div>
<br />
LINK DO DOCUMENTÁRIO QUANDO OS DINOSSAUROS REINAVAM NA TERRA<br />
<div class="separator" style="clear: both; text-align: center;">
<iframe allowfullscreen="" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/hQFgtEnSHzE/0.jpg" frameborder="0" height="266" src="https://www.youtube.com/embed/hQFgtEnSHzE?feature=player_embedded" width="320"></iframe></div>
<div class="separator" style="clear: both; text-align: center;">
<br /></div>
<div class="separator" style="clear: both; text-align: justify;">
LINK DO DOCUMENTÁRIO A ORIGEM DO HOMEM</div>
<div class="separator" style="clear: both; text-align: justify;">
<br /></div>
<div class="separator" style="clear: both; text-align: justify;">
<br /></div>
<div style="text-align: center;">
<iframe allowfullscreen="" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/w8Pp6KmIMu0/0.jpg" frameborder="0" height="266" src="https://www.youtube.com/embed/w8Pp6KmIMu0?feature=player_embedded" width="320"></iframe></div>
<br />
<div class="separator" style="clear: both; text-align: center;">
<br /></div>
<br />Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-70812807607695459452016-11-19T23:04:00.001-03:002016-11-23T16:13:42.885-03:00LINK PARA O EXERCÍCIO DE QUÍMICALINK PARA O EXERCÍCIO DE QUÍMICA - DESLOCAMENTO DO EQUILÍBRIO<br />
<br />
<a href="https://docs.google.com/forms/d/e/1FAIpQLSeJyU_dn-pXWEVxNpl2kqQ6EyUQbnQcKZe4rVVG4ibmtWghlw/viewform">https://docs.google.com/forms/d/e/1FAIpQLSeJyU_dn-pXWEVxNpl2kqQ6EyUQbnQcKZe4rVVG4ibmtWghlw/viewform</a>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-63785751772160146502016-11-16T19:05:00.001-03:002016-11-16T19:05:46.388-03:00Acidificação dos oceanos! - Prof. Cláudio Perdigão<iframe width="480" height="270" src="https://www.youtube.com/embed/2XBv5idrcnA" frameborder="0" allowFullScreen=""></iframe>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-81014362694571810782016-09-13T19:26:00.002-03:002016-09-13T19:26:18.061-03:00LEI DE HESS<div class="subtitulo" style="background-color: white; color: #1365ae; font-family: Arial, Verdana, Helvetica, sans-serif; font-size: 14px; font-weight: bold; margin-bottom: 10px; text-align: justify;">
LEI DE HESS</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
O químico e médico Germain Henry Hess (1802-1850) desenvolveu importantes trabalhos na área de Termoquímica.<br />A <em>Lei de Hess</em> é uma lei experimental e estabelece que a variação de entalpia de uma reação química depende apenas dos estados inicial e final da reação.</div>
<div align="center" style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px;">
<img alt="" height="24" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image080.gif" style="border: 0px;" width="124" /><br />A <em>Lei de Hess</em> também pode ser chamada de <em>Lei da Soma dos Calores de Reação</em>. É uma forma de calcular a variação de entalpia através dos calores das reações intermediárias. Podem ser infinitas variações de entalpia.<br /><img alt="" height="24" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image082.gif" style="border: 0px;" width="191" /><br />Exemplo:<br />Qual o valor da variação de entalpia da reação a seguir?<br /><img alt="" height="25" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image084.gif" style="border: 0px;" width="176" /></div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Dados (equações intermediárias):<br /><img alt="" height="41" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image086.gif" style="border: 0px;" width="327" /><br /><img alt="" height="41" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image088.gif" style="border: 0px;" width="328" /></div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Resolução:<br /><img alt="" height="41" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image086_0000.gif" style="border: 0px;" width="327" /><br /><img alt="" height="41" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image088_0000.gif" style="border: 0px;" width="328" /><br />______________________________________</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
<img alt="" height="25" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image091.gif" style="border: 0px;" width="424" /></div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Observe que a ΔH1e ΔH2 são somadas, obtendo-se o valor da variação de entalpia. As equações químicas também são somadas, obtendo-se a reação global.</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Para montar as equações e aplicar a Lei de Hess, podemos fazer algumas alterações matemáticas, seguindo as seguintes regras:<br />1°) as equações intermediárias devem estar de acordo com a reação global. Coloca-se as equações (dados) na ordem que reagem ou são produzidas. Se não estiverem de acordo, troca-se o sinal da ΔH;<br />2°) acertar os coeficientes também de acordo com a reação global. Se a equação for multiplicada, a ΔH também deve ser multiplicada pelo mesmo número.<br />3°) realizar o somatório para montar a reação global;<br />4°) somar os valores das ΔH das equações intermediárias para achar a ΔH da reação global.</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Exemplo:</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Calcule a variação de entalpia da seguinte reação pela Lei de Hess:<br /><img alt="" height="25" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image093.gif" style="border: 0px;" width="369" /><br /><br />Dados:<br /><img alt="" height="25" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image095.gif" style="border: 0px;" width="371" /><br /><img alt="" height="41" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image097.gif" style="border: 0px;" width="381" /><br /><img alt="" height="25" src="http://www.soq.com.br/conteudos/em/termoquimica/index_clip_image099.gif" style="border: 0px;" width="472" /></div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Resolução:<br />Deve-se escrever todas as equações intermediárias (dados) de acordo com a reação global. Na primeira equação, o que há em comum é o C(grafite). Então ele deve ser escrito da mesma forma (como reagente e 1mol).<br />A segunda equação tem em comum com a reação global o H2(g). Nos dados, esta esécie química não está exatamente igual como na global. Deve-se multiplicar toda a equação por 2, inclusive a ΔH2 <br />A terceira equação tem em comum com a reação global o CH4(g). deve-se inverter a posição desta equação e portanto trocar o sinal da ΔH3</div>
<div style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px; text-align: justify;">
Veja como deve ser feito:</div>
<div align="center" style="background-color: white; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 11px; margin-bottom: 10px;">
<img p="" src="http://www.soq.com.br/conteudos/em/termoquimica/form_h.JPG" style="border: 0px;" /></div>
Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-90015303750186744182016-08-04T12:24:00.003-03:002016-08-04T12:24:59.629-03:00TEORIA DA EVOLUÇÃOESTOU DISPONIBILIZANDO O LINK DO ARQUIVO QUE CONSTA A APOSTILA QUE ESTAMOS TRABALHANDO EM SALA DE AULA, BEM COMO O LINK DO LIVRO A ORIGEM DAS ESPÉCIES DE CHARLES DARWIN<br />
<br />
<a href="http://www.4shared.com/office/ORy297Kvba/TEORIAS_EVOLUCIONISTAS.html">http://www.4shared.com/office/ORy297Kvba/TEORIAS_EVOLUCIONISTAS.html</a><br />
<br />
<a href="http://www.4shared.com/office/Cif5gUrm/darwin_a_origem_das_especies.html">http://www.4shared.com/office/Cif5gUrm/darwin_a_origem_das_especies.html</a><br />
<br />
BASTA CLICAR NO LINK QUE ELE DIRECIONA DIRETO PARA O ARQUIVO.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com1tag:blogger.com,1999:blog-937747745355879544.post-73508333315242098552016-06-13T23:55:00.003-03:002016-06-17T12:51:58.907-03:00EXERCÍCIO DE DILUIÇÃO DE SOLUÇÕES<h1 style="margin: 0cm 0cm 0pt;">
<span style="color: navy; font-family: "arial" , "sans-serif"; font-size: 10pt;"><br /></span></h1>
<h1 style="margin: 0cm 0cm 0pt;">
<span style="color: navy; font-family: "arial" , "sans-serif"; font-size: 10pt;"><div class="MsoNormal" style="text-align: justify;">
<span style="font-size: 12.0pt;">ESCOLA
JOÃO LOPES DE SIQUEIRA SANTOS<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-size: 12.0pt;">DISCIPLINA:
QUÍMICA<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-size: 12.0pt;">ALUNO
(A): ____________________________________ Nº____<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-size: 12.0pt;">SÉRIE
______ TURMA _______ DATA ___/___/___<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-size: 12.0pt;">PROFESSOR:
SERGIVALDO LEITE<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div align="center" class="MsoNormal" style="text-align: center;">
<span style="font-size: 12.0pt;">EXERCÍCIO</span></div>
</span></h1>
<h1 style="margin: 0cm 0cm 0pt;">
<span style="color: navy; font-family: "arial" , "sans-serif"; font-size: 10pt;"><br /></span></h1>
<h1 style="margin: 0cm 0cm 0pt; text-align: center;">
<span style="color: navy; font-family: "arial" , "sans-serif"; font-size: 10pt;">DILUIÇÃO DE SOLUÇÕES<o:p></o:p></span></h1>
<br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1) Uma solução contendo 5 mL de NaCl 1mol/L é diluída com água suficiente para atingir o volume de 500 mL. A concentração desta nova solução é:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,002 mol/L</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,01 mol/L<o:p></o:p></span></div>
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="font-family: "times new roman"; font-size: small;"></span>c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,05 mol/L</span><br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,50 mol/L</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">10 mol/L<o:p></o:p></span></div>
<br />
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt 14.2pt; text-indent: -14.2pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2) A 500 mL de solução 0,5 mol/L de sulfato de sódio são adicionados 750 mL de água. Calcule a molaridade da solução após a diluição.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,33 mol/L.<span style="mso-spacerun: yes;"></span></span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,75 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,20 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1,00 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,25 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">3) Tem-se 600 mL de solução 1,2 mol/L de cloreto de cálcio (CaCl<sub>2</sub>). Calcule a molaridade dessa solução quando seu volume tornar-se 1500 mL através da adição de água.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1,78 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2,78 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,48 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">3,60 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1,20 mol/L.<o:p></o:p></span></div>
<br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">4) Pipetaram-se 10 mL de uma solução aquosa de NaOH de concentração 1,0 mol/L. Em seguida foi<span style="mso-spacerun: yes;"> </span>adicionada água suficiente para atingir o volume final de 500mL. A molaridade da solução final é:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">5,0 . 10<sup>-3</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2,0 . 10<sup>-2</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">5,0 . 10<sup>-2</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,10 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,20 mol/L.<o:p></o:p></span></div>
<br />
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">5) Uma solução contendo 5 mL de NaCl 1 mol/L é diluída com água suficiente para atingir o volume 2500 mL. A concentração desta nova solução será:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,002 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,01 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,05 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,50 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">10,0 mol/L.</span></div>
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"></span><br />
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">6) Uma solução aquosa de ácido sulfúrico, para ser utilizada em baterias de chumbo de veículos, deve apresentar concentração igual a 4 mol/L. O volume total de uma solução adequada para se utilizar nestas ba-terias, que pode ser obtido a partir de 500mL de solução de ácido sulfúrico de concentração 18mol/L, é igual a:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">0,50 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2,00 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="ES-TRAD" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2,25 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">4,50 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">9,00 L.</span></div>
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<br />
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">7) O volume de água, em mL, que deve ser adicionado a 80 mL de solução aquosa 0,1 mol/L de uréia, para<span style="mso-spacerun: yes;"> </span>que a solução resultante seja 0,008 mol/L, deve ser igual a:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">800</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1000</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;"><span style="font-size: 10pt;">c)</span><span style="font-family: "times new roman"; font-stretch: normal;"><span style="font-size: xx-small;"> </span><span style="font-size: x-small;">9</span></span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">20</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">80</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">100</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<br /></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">8) Que volume de água deve-se adicionar a 400 mL de solução 367,5g/L de ácido sulfúrico, para que se torne 122,5g/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">800 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1000 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1800 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">200 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1200 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt; text-align: justify;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">9) Quantos cm<sup>3</sup> de H<sub>2</sub>O temos que adicionar a 1,50 litro de solução 0,50 mol/L, a fim de torná-la 0,20 mol/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1500</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">2250</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1000</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;"><span style="font-size: 10pt;">d)</span><span style="font-family: "times new roman"; font-stretch: normal;"><span style="font-size: xx-small;"> </span><span style="font-size: x-small;">3</span></span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">750</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">500<span style="mso-spacerun: yes;"></span></span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">10) Que volume de água destilada devemos adicionar a 100mL de solução 0,5 mol?l de ácido sulfúrico para que ela se torne 0,1 mol/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">a)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">100 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">b)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">400 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">c)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span lang="EN-US" style="font-family: "arial" , "sans-serif"; font-size: 10pt;">500 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">d)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">550 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<div style="text-indent: -19.6px;">
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><span style="mso-list: Ignore;">e)<span style="font-family: "times new roman"; font-size: 7pt; font-stretch: normal;"> </span></span></span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">1000 mL</span><span style="font-family: "arial" , "sans-serif"; font-size: 10pt;">.</span></div>
<div>
<span style="font-family: "arial" , "sans-serif"; font-size: 10pt;"><br /></span></div>
</div>
Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-70796662369585425862016-03-02T17:54:00.002-03:002016-03-02T17:54:10.890-03:00EXERCÍCIO DE GENÉTICA<div class="MsoNormal">
<span style="font-family: Arial, Helvetica, sans-serif;">Exercício sobre
genética<o:p></o:p></span></div>
<div class="MsoNormal">
<br /></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">1-
(Taubaté) O albinismo nas plantas, ou seja, a incapacidade de sintetizar
clorofila, é um caráter recessivo em muitas espécies. Uma planta de fumo
heterozigota para albinismo é autofecundada, e 600 de suas sementes são postas
para germinar. Quantas teoricamente, levarão a plantas albinas? Quantas,
teoricamente, terão o genótipo parental?<o:p></o:p></span></span></div>
<div style="background: white; font-stretch: inherit; margin: 0cm 0cm 0.0001pt; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">a) 150; 300<o:p></o:p></span></span></div>
<div style="background: white; font-stretch: inherit; margin: 0cm 0cm 0.0001pt; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">b) 150; 450<o:p></o:p></span></span></div>
<div style="background: white; font-stretch: inherit; margin: 0cm 0cm 0.0001pt; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">c) 300; 300<o:p></o:p></span></span></div>
<div style="background: white; font-stretch: inherit; margin: 0cm 0cm 0.0001pt; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">d) 150; 150<o:p></o:p></span></span></div>
<div style="background: white; font-stretch: inherit; margin: 0cm 0cm 0.0001pt; vertical-align: baseline;">
<span style="color: #333333;"><span style="font-family: Arial, Helvetica, sans-serif;">e) 450; 150<o:p></o:p></span></span></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<br /></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-attachment: initial; background-clip: initial; background-image: initial; background-origin: initial; background-position: initial; background-repeat: initial; background-size: initial; color: #333333;">2- (FEEQ-CE) A capacidade de sentir o gosto de uma substância amarga
chamada feniltiocarbamida (PTC) deve-se a um gene dominante. Qual será a
probabilidade de um casal (sensível a essa substância e heterozigótico) ter um
filho sensível ao PTC?</span><o:p></o:p></span></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<br /></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-attachment: initial; background-clip: initial; background-image: initial; background-origin: initial; background-position: initial; background-repeat: initial; background-size: initial; color: #333333;">3- (UFPR) No porquinho da índia, o pêlo pode ser preto ou marrom.
Cruzando-se animais homozigotos de pêlo preto com outros, também homozigotos,
de pêlo marrom, obtiveram-se em F1, todos de pêlo preto. Esses animais F1 foram
retrocruzados com animais de linhagem de pêlo marrom, produzindo 192
descendentes. Quantos se espera que tenham também o pelo marrom?</span><o:p></o:p></span></div>
<div align="left" class="MsoNormal">
<br /></div>
<div align="left" class="MsoNormal">
<span style="background: white; color: #222222; mso-bidi-font-size: 12.0pt; mso-bidi-font-weight: bold; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><span style="font-family: Arial, Helvetica, sans-serif;">4- (UEPB PB) – Sobre o
vocabulário genético, associe corretamente:<o:p></o:p></span></span></div>
<div align="left" class="MsoNormal">
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background: white; color: #222222; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;">I. genótipo;</span><span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><br />
<span style="background: white;">II. fenótipo;</span><br />
<span style="background: white;">III. gene;</span><br />
<span style="background: white;">IV. heredograma. <o:p></o:p></span></span></span></div>
<div align="left" class="MsoNormal">
<br /></div>
<div align="left" class="MsoNormal" style="background: white;">
<span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><span style="font-family: Arial, Helvetica, sans-serif;">A. É a montagem de um grupo familiar
com o uso de símbolos, também conhecido como genealogia, mapa familiar ou
pedigree.<br />
B. Cada segmento de DNA capaz de transcrever sua mensagem em uma molécula de
RNA.<br />
C. É a constituição genética de um organismo, ou seja, o conjunto de alelos que
ele herdou dos genitores.<br />
D. São as características internas ou externas de um ser vivo, geneticamente
determinadas.<o:p></o:p></span></span></div>
<div align="left" class="MsoNormal" style="background: white;">
<span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-bidi-font-weight: bold; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><span style="font-family: Arial, Helvetica, sans-serif;">Assinale a
alternativa correta:<o:p></o:p></span></span></div>
<div align="left" class="MsoNormal" style="background: white;">
<br /></div>
<div align="left" class="MsoNormal" style="background: white;">
<span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><span style="font-family: Arial, Helvetica, sans-serif;">a) I-A ; II-B ; III-D ; IV-C<br />
b) I-C ; II-D ; III-B ; IV-A<br />
c) I-B ; II-A ; III-D ; IV-C<br />
d) I-A ; II-C ; III-B ; IV-D<br />
e) I-D ; II-B ; III-A ; IV-C<o:p></o:p></span></span></div>
<div align="left" class="MsoNormal" style="background: white;">
<br /></div>
<div align="left" class="MsoNormal" style="background: white;">
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-bidi-font-weight: bold; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;">5- (Ufrn
RN) – Em ervilhas, a cor amarela é dominante em relação à verde. Do cruzamento
de heterozigotos, nasceram 720 descendentes. Assinale a opção cujo número
corresponde à quantidade de descendentes amarelos.</span><span style="color: #222222; mso-bidi-font-size: 12.0pt; mso-fareast-font-family: "Times New Roman"; mso-fareast-language: PT-BR;"><br />
a) 360<br />
b) 540<br />
c) 180<br />
d) 720<o:p></o:p></span></span></div>
<div align="left" class="MsoNormal" style="background: white;">
<br /></div>
<div style="background: white; margin-bottom: .0001pt; margin: 0cm; vertical-align: baseline;">
<br /></div>
<br />
<div class="MsoNormal">
<br /></div>
Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-61126214527949008872015-12-02T12:17:00.001-03:002015-12-02T12:17:45.501-03:00VÍDEO AULA SOBRE TÍTULO EM MASSA E RELAÇÃO ENTRE AS CONCENTRAÇÕES<div class="separator" style="clear: both; text-align: center;">
<iframe allowfullscreen='allowfullscreen' webkitallowfullscreen='webkitallowfullscreen' mozallowfullscreen='mozallowfullscreen' width='320' height='266' src='https://www.blogger.com/video.g?token=AD6v5dymDaaj1Mwo5M-stgYXTWOMcATQpckUk1JIKpCv-aj8xHZXUyLvZtWHPoDvZUfcNSTkyQff3Np4SJE5d1IbGA' class='b-hbp-video b-uploaded' frameborder='0'></iframe></div>
<br />
VÍDEO PARA REFORÇO DAS AULAS E REALIZAÇÃO DAS PROVAS FINAISProf Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com3tag:blogger.com,1999:blog-937747745355879544.post-16894160309945502262015-12-01T18:52:00.001-03:002015-12-01T18:52:12.037-03:00VÍDEO AULA CONCENTRAÇÃO COMUM E MOLARLINK DO VÍDEO NO YOUTUBE<br />
<br />
<a href="https://youtu.be/qHOAA18gA4A">https://youtu.be/qHOAA18gA4A</a><br />
<br />
BONS ESTUDOS PESSOALProf Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-32371479845078213792015-11-25T10:29:00.003-03:002015-11-26T12:13:42.310-03:00LINK PARA A VÍDEO AULA DO ESTUDO DOS GASES<br />
CLICK NO LINK ABAIXO PARA DIRECIONÁ-LO À VÍDEO-AULA PARA A AVALIAÇÃO FINAL<br />
<br />
<br />
<a href="https://youtu.be/I6GbkTmlTTQ">https://youtu.be/I6GbkTmlTTQ</a><br />
<br />
BONS ESTUDOSProf Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-27537040651027020242015-11-23T16:46:00.002-03:002015-11-23T16:46:42.156-03:00AUDIO DA AULA DE EQUILÍBRIO QUÍMICO<object data="http://flash-mp3-player.net/medias/player_mp3.swf" height="20" type="application/x-shockwave-flash" width="200">
<param name="movie" value="http://flash-mp3-player.net/medias/player_mp3.swf" />
<param name="bgcolor" value="#ffffff" />
<param name="FlashVars" value="mp3=https%3A//sites.google.com/site/produtosdelimpezaclean/equil%25C3%25ADbrio%2520qu%25C3%25ADmico.mp3" />
</object>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-67684144757432292932015-11-23T16:17:00.005-03:002015-11-23T16:17:31.126-03:00Teoria do Flogisto<object data="http://flash-mp3-player.net/medias/player_mp3.swf" height="20" type="application/x-shockwave-flash" width="200">
<param name="movie" value="http://flash-mp3-player.net/medias/player_mp3.swf" />
<param name="bgcolor" value="#ffffff" />
<param name="FlashVars" value="mp3=https%3A//sites.google.com/site/produtosdelimpezaclean/TEORIA%2520DO%2520FLOGISTO.mp3" />
</object>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-34992192893966004172015-11-23T15:40:00.001-03:002015-11-29T09:55:00.885-03:00BONECO VOKI 2<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=9,0,28,0" height="267" id="widget_name" width="200"><param name="movie" value="http://vhss-d.oddcast.com/vhss_editors/voki_player.swf?doc=http://vhss-d.oddcast.com/php/vhss_editors/getvoki/chsm=763a3db7b4f59f231b57640135af6a15%26sc=12133970" /><param name="quality" value="high" /><param name="allowScriptAccess" value="always" /><param name="width" value="200" /><param name="height" value="267" /><param name="allowNetworking" value="all"/><param name="wmode" value="transparent" /><param name="allowFullScreen" value="true" /><embed height="267" width="200" src="http://vhss-d.oddcast.com/vhss_editors/voki_player.swf?doc=http%3A%2F%2Fvhss-d.oddcast.com%2Fphp%2Fvhss_editors%2Fgetvoki%2Fchsm=763a3db7b4f59f231b57640135af6a15%26sc=12133970" quality="high" allowScriptAccess="always" allowNetworking="all" wmode="transparent" allowFullScreen="true" pluginspage="http://www.adobe.com/shockwave/download/download.cgi?P1_Prod_Version=ShockwaveFlash" type="application/x-shockwave-flash" name="widget_name"></object><br />
<br />
click no botão play para ouvir a mensagem.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-17655437842888959682015-11-22T23:14:00.001-03:002015-11-29T09:55:29.443-03:00boneco voki<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=9,0,28,0" height="267" id="widget_name" width="200"><param name="movie" value="http://vhss-d.oddcast.com/vhss_editors/voki_player.swf?doc=http://vhss-d.oddcast.com/php/vhss_editors/getvoki/chsm=3b12cab20ee1aba433cb3a9c2d4f2ed4%26sc=12129581" /><param name="quality" value="high" /><param name="allowScriptAccess" value="always" /><param name="width" value="200" /><param name="height" value="267" /><param name="allowNetworking" value="all"/><param name="wmode" value="transparent" /><param name="allowFullScreen" value="true" /><embed height="267" width="200" src="http://vhss-d.oddcast.com/vhss_editors/voki_player.swf?doc=http%3A%2F%2Fvhss-d.oddcast.com%2Fphp%2Fvhss_editors%2Fgetvoki%2Fchsm=3b12cab20ee1aba433cb3a9c2d4f2ed4%26sc=12129581" quality="high" allowScriptAccess="always" allowNetworking="all" wmode="transparent" allowFullScreen="true" pluginspage="http://www.adobe.com/shockwave/download/download.cgi?P1_Prod_Version=ShockwaveFlash" type="application/x-shockwave-flash" name="widget_name"></object><br />
<br />
click no botão play para ouvir a mensagem.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-36063708941264973472015-11-22T23:11:00.002-03:002015-11-22T23:11:20.219-03:00quizz<br />
Link que direciona a página do quizz com perguntas de química.<br />
<br />
<a href="http://www.quizzes.com.br/pt/quiz/213965151/quizz-qu-mica">http://www.quizzes.com.br/pt/quiz/213965151/quizz-qu-mica</a>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-8050945879052919292015-11-22T21:30:00.003-03:002015-11-22T23:26:16.330-03:00TABELA PERIÓDICA E BONECO DE PALITOS<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg17Kju-nWfP0gQl3lnVVB7wgVm9DL3p2AEdQo72HNf0mrKVYkTXhKO4E7pkmcHINi97yUVKFlMp2cj61Lt3H_kStVN5D2-5w7YLD202QA0IHzO9Vozua3x5Yh40wc_fmvwWoQC2H0Nvn8/s1600/boneco+de+palitos.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="640" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg17Kju-nWfP0gQl3lnVVB7wgVm9DL3p2AEdQo72HNf0mrKVYkTXhKO4E7pkmcHINi97yUVKFlMp2cj61Lt3H_kStVN5D2-5w7YLD202QA0IHzO9Vozua3x5Yh40wc_fmvwWoQC2H0Nvn8/s640/boneco+de+palitos.jpg" width="492" /></a></div>
<br />
<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYRhgZ9lCOBF3ISTpsffYuRtmK-SX8A99qua4kjgTdxeVMQ6lMAC1zmXjpFOhodTN_ky68A_xtfZ1S2rGxQAdX5_GCPtZvTyXmczg-PHSpWBD1K9luDH_K4ypS7wF4PmxOYw0sSeYGc80/s1600/tabelaquimicanormal.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="245" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYRhgZ9lCOBF3ISTpsffYuRtmK-SX8A99qua4kjgTdxeVMQ6lMAC1zmXjpFOhodTN_ky68A_xtfZ1S2rGxQAdX5_GCPtZvTyXmczg-PHSpWBD1K9luDH_K4ypS7wF4PmxOYw0sSeYGc80/s400/tabelaquimicanormal.jpg" width="400" /></a></div>
<br />Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-80586811390581541012015-11-22T21:22:00.003-03:002015-11-22T21:22:44.477-03:00A SAGA DO PRÊMIO NOBEL<div class="separator" style="clear: both; text-align: center;">
<iframe width="320" height="266" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/FngrM5PeiYc/0.jpg" src="https://www.youtube.com/embed/FngrM5PeiYc?feature=player_embedded" frameborder="0" allowfullscreen></iframe></div>
<br />Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-56726465696423892132015-11-22T21:20:00.001-03:002015-11-22T21:20:06.359-03:00AS 100 MAIORES DESCOBERTAS DA QUÍMICA<div class="separator" style="clear: both; text-align: center;">
<iframe width="320" height="266" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/Iu6iRAYSJZM/0.jpg" src="https://www.youtube.com/embed/Iu6iRAYSJZM?feature=player_embedded" frameborder="0" allowfullscreen></iframe></div>
<br />Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-78778787527032965102015-11-22T21:17:00.002-03:002015-11-22T21:17:18.828-03:00VÍDEO AULA - DESLOCAMENTO DO EQUILÍBRIO <div class="separator" style="clear: both; text-align: center;">
<iframe width="320" height="266" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/8UDt0xhXFiA/0.jpg" src="https://www.youtube.com/embed/8UDt0xhXFiA?feature=player_embedded" frameborder="0" allowfullscreen></iframe></div>
<br />Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-11941820960966511872015-11-22T21:09:00.000-03:002015-11-22T21:09:39.731-03:00EXERCÍCIO DE REVISÃO PARA A PROVA DO 4º BIMESTRE<div class="MsoNormal" style="mso-layout-grid-align: none; text-align: justify; text-autospace: none;">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt;">ESCOLA
DE REFERENCIA JOÃO LOPES DE SIQUEIRA SANTOS<o:p></o:p></span></div>
<div class="MsoNormal" style="mso-layout-grid-align: none; text-align: justify; text-autospace: none;">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt;">DISCIPLINA:
QUÍMICA 2º ANO <b>∙</b>
TURMA:_______<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt;">ALUNO
(A):_________________________________<o:p></o:p></span></div>
<div class="MsoNormal">
<br /></div>
<div align="center" class="MsoNormal" style="text-align: center;">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt;">EXERCÍCIO DE REVISÃO<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">01) A relação a seguir mostra a variação da concentração
de uma substância </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">A</span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">, em função do tempo, em<o:p></o:p></span></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shapetype
id="_x0000_t32" coordsize="21600,21600" o:spt="32" o:oned="t" path="m,l21600,21600e"
filled="f">
<v:path arrowok="t" fillok="f" o:connecttype="none"/>
<o:lock v:ext="edit" shapetype="t"/>
</v:shapetype><v:shape id="_x0000_s1027" type="#_x0000_t32" style='position:absolute;
margin-left:206.25pt;margin-top:11pt;width:.75pt;height:16.5pt;z-index:251648512'
o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 274px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251648512;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1027" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1028"
type="#_x0000_t32" style='position:absolute;margin-left:183pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251649536' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 243px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251649536;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1028" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1029"
type="#_x0000_t32" style='position:absolute;margin-left:160.5pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251650560' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 213px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251650560;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1029" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1030"
type="#_x0000_t32" style='position:absolute;margin-left:139.5pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251651584' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 185px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251651584;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1030" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1031"
type="#_x0000_t32" style='position:absolute;margin-left:117pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251652608' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 155px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251652608;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1031" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1032"
type="#_x0000_t32" style='position:absolute;margin-left:99pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251653632' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 131px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251653632;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1032" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1033"
type="#_x0000_t32" style='position:absolute;margin-left:81pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251654656' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 107px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251654656;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1033" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1034"
type="#_x0000_t32" style='position:absolute;margin-left:63pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251655680' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 83px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251655680;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1034" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1035"
type="#_x0000_t32" style='position:absolute;margin-left:45.75pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251656704' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 60px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251656704;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1035" width="3" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1036"
type="#_x0000_t32" style='position:absolute;margin-left:27pt;margin-top:11pt;
width:.75pt;height:16.5pt;z-index:251657728' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 24px; margin-left: 35px; margin-top: 14px; mso-ignore: vglayout; position: absolute; width: 3px; z-index: 251657728;"><img height="24" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image001.png" v:shapes="_x0000_s1036" width="3" /></span><!--[endif]--><span style="font-family: Arial, sans-serif; font-size: 10pt;">uma
reação química: </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">a A + b B ↔</span></b><span style="color: navy; font-family: TT6C3o00; font-size: 10.0pt; mso-bidi-font-family: TT6C3o00; mso-fareast-font-family: Calibri;"> </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">c C + d D<o:p></o:p></span></b></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1026" type="#_x0000_t32" style='position:absolute;margin-left:-2.25pt;
margin-top:8.5pt;width:243pt;height:0;z-index:251647488' o:connectortype="straight"/><![endif]--><!--[if !vml]--><span style="height: 2px; margin-left: -4px; margin-top: 10px; mso-ignore: vglayout; position: absolute; width: 326px; z-index: 251647488;"><img height="2" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image002.png" v:shapes="_x0000_s1026" width="326" /></span><!--[endif]--><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">T(min) 0,0
2,0 4,0 6,0
8,0 10,0 12,0
14,0 16,0 18,0</span></b><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;"><o:p></o:p></span></b></div>
<div class="MsoNormal">
<b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">[A] 11,0 7,0
4,3 3,0 2,0
1,0 0,5 0,3
0,2 0,2</span></b><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;"><o:p></o:p></span></b></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">Qual será o valor da velocidade média da reação de </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">A </span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">correspondente
ao intervalo entre 4 e 14 min?<o:p></o:p></span></div>
<div class="MsoNormal">
<span lang="EN-US" style="font-family: Arial, sans-serif; font-size: 10pt;">a) 4,0 mol/L.min.<o:p></o:p></span></div>
<div class="MsoNormal">
<span lang="EN-US" style="font-family: Arial, sans-serif; font-size: 10pt;">b) 0,4 mol/L.min.<o:p></o:p></span></div>
<div class="MsoNormal">
<span lang="EN-US" style="font-family: Arial, sans-serif; font-size: 10pt;">c) 1,4 mol/L.min.<o:p></o:p></span></div>
<div class="MsoNormal">
<span lang="EN-US" style="font-family: Arial, sans-serif; font-size: 10pt;">d) 25 mol/L.min.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
2,5 mol/L.min.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1042" type="#_x0000_t32" style='position:absolute;margin-left:93.75pt;
margin-top:6.85pt;width:16.5pt;height:0;flip:x;z-index:251663872'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 123px; margin-top: 3px; mso-ignore: vglayout; position: absolute; width: 25px; z-index: 251663872;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image003.png" v:shapes="_x0000_s1042" width="25" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1041"
type="#_x0000_t32" style='position:absolute;margin-left:96pt;margin-top:2.35pt;
width:17.25pt;height:0;z-index:251662848' o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="mso-ignore: vglayout; position: relative; z-index: 251662848;"><span style="height: 12px; left: 127px; position: absolute; top: -3px; width: 26px;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image004.png" v:shapes="_x0000_s1041" width="26" /></span></span><!--[endif]--><span style="font-family: Arial, sans-serif; font-size: 10pt;">02)
A reação </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">A + 2 B </span></b><span style="color: navy; font-family: TT736o00; font-size: 10.0pt; mso-bidi-font-family: TT736o00; mso-fareast-font-family: Calibri;"> </span><b><span style="color: navy; font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">P </span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">se processa em
uma única etapa. Qual a velocidade desta reação quando K =<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">0,3 L/mol.min, [A] = 2,0 M e [B] = 3,0 M ?<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) 5,4.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 4,5.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 1,8.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 18,0.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
54.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1040" type="#_x0000_t32" style='position:absolute;margin-left:150pt;
margin-top:66.15pt;width:16.5pt;height:0;flip:x;z-index:251661824'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 198px; margin-top: 82px; mso-ignore: vglayout; position: absolute; width: 25px; z-index: 251661824;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image003.png" v:shapes="_x0000_s1040" width="25" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1039"
type="#_x0000_t32" style='position:absolute;margin-left:149.25pt;margin-top:61.65pt;
width:17.25pt;height:0;z-index:251660800' o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 198px; margin-top: 76px; mso-ignore: vglayout; position: absolute; width: 26px; z-index: 251660800;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image004.png" v:shapes="_x0000_s1039" width="26" /></span><!--[endif]--><span style="font-family: Arial, sans-serif; font-size: 10pt;">03)
(UNAERP-SP) Se tivermos em um recipiente, à temperatura ambiente, dois gases
prontos para reagir, segundo a reação elementar abaixo, o que acontecerá com a
velocidade de reação dos gases se, em um dado momento, apenas dobrarmos as concentrações
molares dos gases: </span><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">A</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 6.5pt; mso-fareast-font-family: Calibri;">(g) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">+ 3 B</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 6.5pt; mso-fareast-font-family: Calibri;">(g) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">2 C</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 6.5pt; mso-fareast-font-family: Calibri;">(g)</span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;"><o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) A velocidade da reação aumentará 16 vezes.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) A velocidade da reação duplicará.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) A velocidade da reação permanecerá a mesma.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) A velocidade da reação será reduzida à metade.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
A velocidade da reação aumentará 4 vezes.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">04)Em determinadas condições de temperatura e pressão,
existe 0,5 mol / L de N</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">O</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">4 </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">em equilíbrio com<o:p></o:p></span></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1037" type="#_x0000_t32" style='position:absolute;margin-left:213.75pt;
margin-top:3.15pt;width:21.75pt;height:.05pt;z-index:251658752'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="mso-ignore: vglayout; position: relative; z-index: 251658752;"><span style="height: 12px; left: 284px; position: absolute; top: -2px; width: 32px;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image005.png" v:shapes="_x0000_s1037" width="32" /></span></span><!--[endif]--><!--[if gte vml 1]><v:shape
id="_x0000_s1038" type="#_x0000_t32" style='position:absolute;margin-left:213.75pt;
margin-top:8.4pt;width:21.75pt;height:0;flip:x;z-index:251659776'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 283px; margin-top: 5px; mso-ignore: vglayout; position: absolute; width: 32px; z-index: 251659776;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image006.png" v:shapes="_x0000_s1038" width="32" /></span><!--[endif]--><span style="font-family: Arial, sans-serif; font-size: 10pt;">2,0
mols/ L de NO</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">, segundo a reação N</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">O</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">4</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">(g) </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">2 NO</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">(g). Então, a constante de equilíbrio, K</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">c</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">, deste equilíbrio, nas condições
da experiência, numericamente igual a:</span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) 0,125.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 0,25.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 1.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 4.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">e) 8.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">05) Para a reação a seguir:<o:p></o:p></span></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1044" type="#_x0000_t32" style='position:absolute;margin-left:75pt;
margin-top:6.65pt;width:24.75pt;height:0;flip:x;z-index:251665920'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 98px; margin-top: 3px; mso-ignore: vglayout; position: absolute; width: 36px; z-index: 251665920;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image007.png" v:shapes="_x0000_s1044" width="36" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1043"
type="#_x0000_t32" style='position:absolute;margin-left:77.25pt;margin-top:2.85pt;
width:21.75pt;height:.05pt;z-index:251664896' o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="mso-ignore: vglayout; position: relative; z-index: 251664896;"><span style="height: 12px; left: 102px; position: absolute; top: -2px; width: 32px;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image008.png" v:shapes="_x0000_s1043" width="32" /></span></span><!--[endif]--><b><span style="font-family: "Arial",sans-serif; font-size: 9.5pt; mso-fareast-font-family: Calibri;">2 CO</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">( g) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 9.5pt; mso-fareast-font-family: Calibri;">+ O</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">2( g) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 9.5pt; mso-fareast-font-family: Calibri;">2 CO</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">2 ( g) </span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">realizada
a uma dada temperatura, o valor da constante de equilíbrio é 40 e as
concentrações molares</span><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;"> </span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">do
CO</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">(g) </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">e CO</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2(g) </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">valem respectivamente 0,05 mol/L e 0,10 mol/L. Calcule a
molaridade do O</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2(g)</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">.</span><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;"><o:p></o:p></span></b></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) 0,10.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 0,20.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 0,30.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 0,40.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
0,50.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">06) (UFMG) O hidróxido de amônio, NH</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">4</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">OH</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">(aq)</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">, em solução 10 <sup>– 2</sup></span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;"> </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">mol/L, apresenta grau de
dissociação 1% à temperatura ambiente. Sua constante de dissociação valerá,
aproximadamente, nessa temperatura:<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">a) 10 <sup>– 6</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 10 <sup>– 3</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 10 <sup>– 2</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 10 <sup>3</sup>.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
10 <sup>6</sup>.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">07)(FAMECA-SP) Qual o valor de “K</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">i</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">” para o HCN, sabendo-se que o
ácido em solução 0,10 mol/L<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">encontra-se 0,006% ionizado?<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) 1,2 x 10 <sup>– 4</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">b) 3,6 x 10 <sup>– 10</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 3,6 x 10 <sup>– 8</sup>.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 3,6 x 10 <sup>– 5</sup>.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
6,0 x 10 <sup>– 5</sup>.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">08)O vinagre pode ser considerado uma solução de
concentração 0,72 mol/L em relação ao ácido acético.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">Esse ácido é fraco e possui constante de ionização (K</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">a</span><span style="font-family: Arial, sans-serif; font-size: 10pt;">) igual a 1,8 x 10 <sup>– 5</sup>,
a 25°C. Nessa temperatura, o grau de ionização do ácido acético é igual a:<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">a) 0,5 %.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 0,05 %.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 0,005 %.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 5,0 %.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e)
0,0005 %.<o:p></o:p></span></div>
<div class="MsoNormal" style="text-align: justify;">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">09)FACHA
(MG) A reação abaixo: <o:p></o:p></span></div>
<div class="MsoNormal">
<b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt;">CH<sub>4</sub> ( g )+ H<sub>2</sub>O
( g ) < = > CO( g )+ 3 H<sub>2</sub> ( g )</span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;"> representa
uma fonte de hidrogênio. A 2000K, o valor de Kc é 4,0, qual o valor de Kp? Dado
R= 0,082 atmL/Kmol<o:p></o:p></span></div>
<div class="MsoNormal">
<br /></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">10) A altas temperaturas, N</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2 </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">reage com O</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2 </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">produzindo NO, um poluente
atmosférico:<o:p></o:p></span></div>
<div class="MsoNormal">
<!--[if gte vml 1]><v:shape
id="_x0000_s1045" type="#_x0000_t32" style='position:absolute;margin-left:69.4pt;
margin-top:8.3pt;width:23.25pt;height:.05pt;flip:x;z-index:251666944'
o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="height: 12px; margin-left: 91px; margin-top: 5px; mso-ignore: vglayout; position: absolute; width: 34px; z-index: 251666944;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image009.png" v:shapes="_x0000_s1045" width="34" /></span><!--[endif]--><!--[if gte vml 1]><v:shape id="_x0000_s1046"
type="#_x0000_t32" style='position:absolute;margin-left:70.9pt;margin-top:3.05pt;
width:21.75pt;height:.05pt;z-index:251667968' o:connectortype="straight">
<v:stroke endarrow="block"/>
</v:shape><![endif]--><!--[if !vml]--><span style="mso-ignore: vglayout; position: relative; z-index: 251667968;"><span style="height: 12px; left: 94px; position: absolute; top: -2px; width: 32px;"><img height="12" src="file:///C:/Users/PROFSE~1/AppData/Local/Temp/msohtmlclip1/01/clip_image010.png" v:shapes="_x0000_s1046" width="32" /></span></span><!--[endif]--><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">N</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">2 ( g ) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">+ O</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">2 ( g) </span></b><b><span style="font-family: "Arial",sans-serif; font-size: 10.0pt; mso-fareast-font-family: Calibri;">2 NO</span></b><b><span style="font-family: "Arial",sans-serif; font-size: 8.0pt; mso-fareast-font-family: Calibri;">( g) </span></b><span style="font-family: Arial, sans-serif; font-size: 10pt;">À temperatura de 2000 K, a constante de equilíbrio dada é
igual a 4,0 x 10 <sup>– 4</sup>. Nesta temperatura, se as concentrações de
equilíbrio de N</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2 </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">e O</span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;">2 </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">forem, respectivamente, 4,0 x 10 <sup>– 3</sup></span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;"> </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">e </span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">1,0 x 10 <sup>– 3</sup></span><span style="font-family: Arial, sans-serif; font-size: 6.5pt;"> </span><span style="font-family: Arial, sans-serif; font-size: 10pt;">mol/L, qual será a do NO?</span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">a) 1,6 x 10 <sup>– 9</sup> mol/L.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">b) 4,0 x 10 <sup>– 9</sup> mol/L.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">c) 1,0 x 10 <sup>– 5</sup> mol/L.<o:p></o:p></span></div>
<div class="MsoNormal">
<span style="font-family: Arial, sans-serif; font-size: 10pt;">d) 4,0 x 10 <sup>– 5</sup> mol/L.<o:p></o:p></span></div>
<span style="font-family: Arial, sans-serif; font-size: 10pt;">e) 1,6 x 10 </span><sup style="font-family: Arial, sans-serif;">– 4</sup><span style="font-family: Arial, sans-serif; font-size: 10pt;"> mol/L.</span>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-87084635166847254172015-11-11T14:07:00.000-03:002015-11-11T14:07:52.606-03:00Vídeo aula de Equilíbrio Químicolink do vídeo no youtube<br />
<br />
<a href="https://youtu.be/8UDt0xhXFiA">https://youtu.be/8UDt0xhXFiA</a><br />
<br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; font-size: 11.88px; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<b><span style="font-family: "verdana" , sans-serif; font-size: 14pt;">EXERCICIO DE EQUILIBRIO QUÍMICO </span></b><b style="font-size: 11.88px; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif; font-size: 14pt;">2º ANO</span></b></div>
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; font-size: 11.88px; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<b style="font-size: 11.88px; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif; font-size: 14pt;"><br /></span></b></div>
<span style="font-size: x-small;"><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">01.</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> (PUC) O equilíbrio químico representado pela equação: </span></span><br />
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">N<sub>2(g)</sub> + O<sub>2(g)</sub> D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 NO<sub>(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "symbol";">D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">H</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">= +21,6 Kcal, apresentará rendimento máximo em NO<sub>(g)</sub>: </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) em temperatura e pressões elevadas; </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) em temperaturas e pressões baixas; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) em temperaturas elevadas e pressões baixas; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) em temperaturas elevadas independentemente da pressão; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) em pressões altas independentemente da temperatura. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">02.</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> (UnB) Um dos processos de fabricação de H<sub>2</sub> consiste em passar uma mistura de monóxido de carbono e vapor d’água sobre um catalisador adequado, à temperatura de 50°C. A reação é a seguinte: </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">CO + H<sub>2</sub>O </span></b><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">D</span></b><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;"> CO<sub>2</sub> + H<sub>2</sub></span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">O procedimento <span style="text-transform: uppercase;">CORRETO</span> para a obtenção de um rendimento de hidrogênio, é: <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) diminuir a concentração de monóxido de carbono; </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) injetar gás carbônico em excesso; </span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif; line-height: 16.632px;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) injetar vapor d’água em excesso; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) nenhuma dessas. </span></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">03.</span></b><span style="font-family: "verdana" , sans-serif;"> (OSEC) Na reação: N<sub>2(g)</sub> + 3 H<sub>2(g)</sub> D</span><span style="font-family: "verdana" , sans-serif;"> 2 NH<sub>3(g)</sub> </span><span style="font-family: "symbol";">D</span><span style="font-family: "verdana" , sans-serif;">H</span><span style="font-family: "verdana" , sans-serif;"> = -22,0 Kcal, a quantidade máxima de NH<sub>3(g) </sub>se formará, quando:</span><span style="font-family: "verdana" , sans-serif;"><o:p></o:p></span></span></div>
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) A temperatura e a pressão aumentarem simultaneamente. </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) A temperatura e a pressão diminuírem simultaneamente. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) A temperatura diminuir e a pressão aumentar. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) A temperatura aumentar e a pressão diminuir. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) A concentração de nitrogênio diminuir <o:p></o:p></span></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">04</span></b><b><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="font-family: "verdana" , sans-serif;"> (CESGRANRIO) A equação química abaixo representa um sistema gasoso em equilíbrio:</span><span style="font-family: "verdana" , sans-serif;"><o:p></o:p></span></span></div>
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> (2)</span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">2 SO<sub>2(g)</sub> + O<sub>2(g) </sub></span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 SO<sub>3</sub> <sub>(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "symbol";">D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">H < 0 <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><span style="font-family: "times new roman";"> </span>(1)</span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">Em relação ao mesmo sistema, são feitas as seguintes afirmações: <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">I. Se a concentração do SO<sub>2(g)</sub> for aumentada, o equilíbrio se desloca no sentido (1). </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">II. Se a pressão parcial de SO<sub>3(g)</sub> é reduzida, o equilíbrio se desloca no sentido (1). <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">III. Se a temperatura do sistema é reduzida, o equilíbrio se desloca no sentido (2). <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">IV. Se a pressão total do sistema é reduzida, o equilíbrio se desloca no sentido (1). <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">V. Se um catalisador é introduzido no sistema, o equilíbrio não se altera. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">Estão corretas somente: <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) I, III e IV </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) III, IV e V </span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) I, II e III <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) I, II e V </span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) II, IV e V <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">05</span></b><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> (FATEC) A equação representada um sistema em equilíbrio: </span></span><br />
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">H<sub>2(g)</sub> + C<i>l</i><sub>2(g)</sub> D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 HC<i>l</i><sub>(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "symbol";">D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">H = -22,0 Kcal/mol <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">A concentração de equilíbrio do HC<i>l</i> poderá ser aumentada se houver: <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) aumento da temperatura; </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) aumento da pressão; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) diminuição da pressão; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) adição de um catalisador;<o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) aumento de concentração de H<sub>2</sub>.</span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">06</span></b><b><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="font-family: "verdana" , sans-serif;"> (UFGO) A seguir são apresentados cinco equilíbrios químicos. Assinale aquele que não sofre deslocamento com aumento de pressão: </span><span style="font-family: "verdana" , sans-serif;"> </span><span style="font-family: "times new roman" , serif;"><o:p></o:p></span></span></div>
<span style="font-size: x-small;"><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">SO<sub>2</sub>C<i>l</i><sub>2(g)</sub> </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">D SO<sub>2(g)</sub> + C<i>l</i><sub>2(g)</sub> </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) SbC<i>l</i><sub>5(g)</sub> D SbC<i>l</i><sub>3(g)</sub> + C<i>l</i><sub>2(g)</sub> </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">C<sub>(s)</sub> + CO<sub>2(g)</sub> </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">D</span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 CO<sub>(g)</sub> <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) 2 HI<sub>(g)</sub> D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> H<sub>2(g)</sub> + I<sub>2(g)</sub></span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) 2 H<sub>2</sub>S<sub>(g) </sub> D </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 H<sub>2(g)</sub> + S<sub>2(g)</sub></span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">07</span></b><b><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="font-family: "verdana" , sans-serif;"> (PUCC) Assinale o equilíbrio que não se altera pela mudança de pressão, sob temperatura constante:</span><span style="font-family: "verdana" , sans-serif;"><o:p></o:p></span></span></div>
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) 2 NOC<i>l</i><sub>(g) </sub> D 2 NO<sub>(g)</sub> + C<i>l</i><sub>2(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) 2 NH<sub>3(g)</sub> D N<sub>2(g)</sub> + 3 H<sub>2(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">PC<i>l</i><sub>5(g)</sub> </span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">D</span><span lang="EN-US" style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> PC<i>l</i><sub>3(g)</sub> + C<i>l</i><sub>2(g)</sub> <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) N<sub>2</sub>O<sub>4(g)</sub> D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> 2 NO<sub>2(g)</sub><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) n.d.a.</span><span style="background-color: white; color: #333333; font-family: "times new roman" , serif;"><o:p></o:p></span></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">08</span></b><b><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="font-family: "verdana" , sans-serif;"> (OSEC) O éter dimetílico, quando aquecido em recipiente fechado e à temperatura constante pode se decompor conforme a equação:</span><span style="font-family: "verdana" , sans-serif;"><o:p></o:p></span></span></div>
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">H<sub>3</sub>C – O – CH<sub>3(g)</sub> </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">D</span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> CH<sub>4(g)</sub> + CO<sub>(g)</sub> + H<sub>2(g)</sub> <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">Durante o andamento desta decomposição é errado dizermos que: <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">a) o número total de moles da mistura gasosa aumenta; </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"><o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">b) a pressão total da mistura gasosa permanece constante; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">c) a pressão parcial do H<sub>2</sub> é igual à do CH<sub>4</sub>; <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">d) o número de moles do H<sub>2</sub> é igual ao número de moles de CO. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">e) n.d.a. <o:p></o:p></span><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;"><br /></span></b></span><br />
<span style="font-size: x-small;"><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">As duas questões seguintes devem ser respondidas de acordo com o código: <o:p></o:p></span></b><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">a)</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">aumento de volume; <o:p></o:p></span></b><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">b)</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">aumento no tempo da reação; <o:p></o:p></span></b><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">c)</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">passagem de corrente elétrica; <o:p></o:p></span></b><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">d)</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">aumento da concentração de hidrogênio gasoso; <o:p></o:p></span></b><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">e)</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> </span><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">adição de catalisador. <o:p></o:p></span></b></span><br />
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><b><span style="font-family: "verdana" , sans-serif;">09</span></b><b><span style="font-family: "verdana" , sans-serif;">.</span></b><span style="font-family: "verdana" , sans-serif;"> (USP) Qual das alterações mencionadas acima influi no equilíbrio </span></span></div>
<div class="MsoNormal" style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px; margin: 0cm 0cm 0pt;">
<span style="font-size: x-small;"><span style="font-family: "verdana" , sans-serif;">H<sub>2(g)</sub> + O<sub>2(g)</sub> D</span><span style="font-family: "verdana" , sans-serif;"> H<sub>2</sub>O<sub>2(g)</sub>, de modo a aumentar a concentração de H<sub>2</sub>O<sub>2(g)</sub>?</span></span></div>
<span style="font-size: x-small;"><br style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;" /><b style="background-color: white; color: #333333; font-family: Arial, Tahoma, Helvetica, FreeSans, sans-serif; line-height: 16.632px;"><span style="font-family: "verdana" , sans-serif;">10.</span></b><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;"> (USP) Qual das alterações mencionadas acima influi no equilíbrio, </span></span><br />
<span style="font-size: x-small;"><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">N<sub>2</sub>H<sub>4 (g)</sub> D </span><span style="background-color: white; color: #333333; font-family: "verdana" , sans-serif;">N<sub>2(g)</sub> + 2 H<sub>2(g)</sub>, de modo a aumentar a quantidade de N<sub>2(g)</sub>? <o:p></o:p></span></span><br />
<span style="font-size: x-small;"><br /></span>
<span style="color: red; font-family: "verdana" , sans-serif; font-size: x-small;"><span style="background-color: white; line-height: 16.632px; text-transform: uppercase;"><b>OBS: A LETRA D ENTRE O REAGENTE E O PRODUTO ESTÁ REPRESENTANDO A DUPLA SETA.</b></span></span>Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-29831528951955915692015-10-29T14:13:00.000-03:002016-09-26T16:25:20.108-03:00exercício de cinética química1) A reação 2 A + B <span style="font-family: "arial" , sans-serif; font-size: 16pt; line-height: 107%;">→</span> P, apresenta uma lei de velocidade expressa por v = k [A]2. Se a concentração do reagente A for mantida constante e a de B for duplicada, a velocidade da reação fica multiplicada por<br />
um fator igual a:<br />
a) 0.<br />
b) 1.<br />
c) 2.<br />
d) 3.<br />
e) 4.<br />
2) A reação NO2(g) + CO(g) <span style="font-family: "arial" , sans-serif; font-size: 16pt; line-height: 107%;">→</span> CO2(g) + NO(g) é de segunda ordem em relação ao NO2(g) e de ordem zero em relação ao CO(g). Em determinadas condições de temperatura e pressão, essa reação ocorre com<br />
velocidade v. Se triplicarmos a concentração de NO2(g) e duplicarmos a concentração de CO(g), a nova<br />
velocidade de reação v’ será igual a:<br />
a) 3v.<br />
b) 6v.<br />
c) 9v.<br />
d) 12v.<br />
e) 18v.<br />
<br />
3) Dada a equação da reação elementar H2 + Cl2 <span style="font-family: "arial" , sans-serif; font-size: 16pt; line-height: 107%;">→</span> 2 HCl, se reduzirmos simultaneamente a<br />
concentração de H2 e Cl2 à metade, mantendo-se constantes todos os outros fatores, a velocidade da<br />
reação:<br />
a) quadruplica.<br />
b) reduz-se a um quarto da inicial.<br />
c) dobra.<br />
d) reduz-se à metade.<br />
e) permanece igual à inicial.<br />
<br />
4) (UNAERP-SP) Se tivermos em um recipiente, à temperatura ambiente, dois gases prontos para reagir, segundo a reação elementar abaixo, o que acontecerá com a velocidade de reação dos gases se, em um dado momento, apenas dobrarmos as concentrações molares dos gases:<br />
A(g) + 3 B(g) <span style="font-family: "arial" , sans-serif; font-size: 16pt; line-height: 107%;">→</span> 2 C(g)<br />
a) A velocidade da reação aumentará 16 vezes.<br />
b) A velocidade da reação duplicará.<br />
c) A velocidade da reação permanecerá a mesma.<br />
d) A velocidade da reação será reduzida à metade.<br />
e) A velocidade da reação aumentará 4 vezes.<br />
<br />
5)(Fuvest-SP) O estudo de certa reação química é representada por 2 A (g) + 2 B (g) <span style="font-family: "arial" , sans-serif; font-size: 16pt; line-height: 107%;">→</span> C (g) onde A, B e C significam as espécies químicas que são colocadas para reagir. Verificou-se<br />
experimentalmente, numa certa temperatura, que a velocidade dessa reação quadruplica com a<br />
duplicação da concentração da espécie A, mas não depende das concentrações das espécies B e C.<br />
Assinale a opção que contém, respectivamente, a expressão correta da velocidade e o valor da ordem<br />
da reação:<br />
a) v = k [A]2{B]2 e 4.<br />
b) v = k [A]2[B]2 e 3.<br />
c) v = k [A]2[B]2 e 2.<br />
d) v = k [A]2 e 4.<br />
e) v = k [A]2 e 2.Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-5592676618487025872015-07-16T09:46:00.002-03:002015-07-16T09:46:52.102-03:00Espermatozoide de 50 milhões de anos é encontrado na Antártica<h1 class="entry-title" style="background: rgb(255, 255, 255); color: #333333; font-family: arial, helvetica, freesans, sans-serif; font-size: 3.16em; letter-spacing: -0.06em; margin: 0px; outline: 0px; padding: 0px;">
Espermatozoide de 50 milhões de anos é encontrado na Antártica</h1>
<h2 style="background: rgb(255, 255, 255); color: #929292; font-family: arial, helvetica, freesans, sans-serif; font-weight: normal; letter-spacing: -0.01em; line-height: 1.2em; margin: 0px; outline: 0px; padding: 0.3em 0px 0px;">
Espermatozóide pertence a família que inclui minhocas e sanguessugas; descoberta foi feita por acaso.</h2>
<div>
<img alt="Acredita-se que espermatozóide seja o mais antigo já encontrado (Foto: Biology Letters/BBC)" height="223" src="http://s2.glbimg.com/mZrymlVu2YWsUBnP7V_4DuCt9pw=/s.glbimg.com/jo/g1/f/original/2015/07/16/espermatozoide.jpg" width="400" /></div>
<div>
<span style="background: rgb(238, 238, 238); display: block; font-family: arial, helvetica, freesans, sans-serif; margin: 0px; outline: 0px; padding: 0.67em;"><span style="font-size: xx-small;">Acredita-se que espermatozóide seja o mais antigo já encontrado (Foto: Biology Letters/BBC)</span></span><span style="background: rgb(238, 238, 238); display: block; font-family: arial, helvetica, freesans, sans-serif; margin: 0px; outline: 0px; padding: 0.67em;"><div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
Especialistas descobriram um espermatozoide animal de 50 milhões de anos, o mais antigo já encontrado. A descoberta foi num casulo na Antártica.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
O espermatozoide pertence a uma família que inclui minhocas e sanguessugas, segundo os pesquisadores do Museu Sueco de História Nacional.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
Acredita-se que a descoberta, divulgada na publicação Biology Letters, seja 10 milhões de anos mais velha que o registro anterior.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
Cientistas dizem que o esperma fóssil Clitellata é muito parecido com o esperma de vermes de lagostas, que se alimentam de matérias encontradas na parte externa do corpo do animal.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
"Pode parecer que (a amostra) esteja preservada em detalhes perfeitos mas, no final, a estrutura em si está fossilizada", disse o paleontologista Benjamin Bomfleur, da equipe que fez a descoberta.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
"Temos a forma exterior e a forma das células do espermatozoide preservadas. Podemos até ter uma formação anatômica interna das células do espermatozoide ainda preservada, mas não temos certeza sobre isso ainda."</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
"Mas, mesmo se a anatomia estiver preservada, o material que o compõe está alterado, então não é o material orgânico original que compõe o esperma passado dos animais."</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
A descoberta foi feita por acaso por Stephen McLoughlin, que integra a equipe de Bomfleur, enquanto ele analisava amostras de rochas da Antártica.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
Segundo Bomfleur, ambos já haviam estudado casulos fossilizados e sabiam que eles poderiam conter micro-organismos.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
"Analisamos os casulos com cuidado e os analisamos através de diferentes métodos microscópicos para ver se há alguma coisa dentro", diz. "Mas foi uma surpresa encontrar esperma."</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
A equipe quer, agora, analisar mais exames de casulos antigos, na perspectiva de que descobertas semelhantes podem ser feitas.</div>
<div style="background: rgb(255, 255, 255); color: #333333; letter-spacing: -0.02em; line-height: 1.45em; outline: 0px; padding: 0px 0px 1.5em;">
"Acreditamos que levantamentos de casulos antigos podem abrir uma janela única para a história evolutiva de uma gama de micro-organismos invertebrados que não têm registro fóssil", diz o artigo.</div>
</span></div>
<div>
<br /></div>
Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com0tag:blogger.com,1999:blog-937747745355879544.post-79318124281684833932015-06-25T16:25:00.003-03:002016-07-10T19:05:40.592-03:00<br />
<span style="color: red; font-size: large;">Exercicio de reforço para estudar para a prova de quimica</span><br />
<h1 style="margin: 0cm 0cm 0pt;">
<span style="color: navy; font-family: "Arial","sans-serif"; font-size: 10pt;">DILUIÇÃO DE SOLUÇÕES<o:p></o:p></span></h1>
<br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1) Uma solução contendo 5 mL de NaCl 1mol/L é diluída com água suficiente para atingir o volume de 500 mL. A concentração desta nova solução é:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,002 mol/L</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,01 mol/L<o:p></o:p></span></div>
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;"><span style="font-family: Times New Roman; font-size: small;"> </span>c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,05 mol/L</span><br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,50 mol/L</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l0 level1 lfo1; tab-stops: list 39.0pt; text-align: justify; text-indent: -24.8pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">10 mol/L<o:p></o:p></span></div>
<br />
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt 14.2pt; text-indent: -14.2pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">2) A 500 mL de solução 0,5 mol/L de sulfato de sódio são adicionados 750 mL de água. Calcule a molaridade da solução após a diluição.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,33 mol/L.<span style="mso-spacerun: yes;"> </span></span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,75 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,20 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">1,00 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,25 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">3) Tem-se 600 mL de solução 1,2 mol/L de cloreto de cálcio (CaCl<sub>2</sub>). Calcule a molaridade dessa solução quando seu volume tornar-se 1500 mL através da adição de água.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">1,78 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">2,78 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,48 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">3,60 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l1 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -26pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">1,20 mol/L.<o:p></o:p></span></div>
<br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 14.2pt; text-align: justify; text-indent: -14.2pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">4) Pipetaram-se 10 mL de uma solução aquosa de NaOH de concentração 1,0 mol/L. Em seguida foi<span style="mso-spacerun: yes;"> </span>adicionada água suficiente para atingir o volume final de 500mL. A molaridade da solução final é:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">5,0 . 10<sup>-3</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">2,0 . 10<sup>-2</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">5,0 . 10<sup>-2</sup>mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,10 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l2 level1 lfo2; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,20 mol/L.<o:p></o:p></span></div>
<br />
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold;">5) Uma solução contendo 5 mL de NaCl 1 mol/L é diluída com água suficiente para atingir o volume 2500 mL. A concentração desta nova solução será:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">0,002 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">0,01 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">0,05 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">0,50 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l5 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -21.8pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold;">10,0 mol/L.</span></div>
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;"></span><br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">6) Uma solução aquosa de ácido sulfúrico, para ser utilizada em baterias de chumbo de veículos, deve apresentar concentração igual a 4 mol/L. O volume total de uma solução adequada para se utilizar nestas ba-terias, que pode ser obtido a partir de 500mL de solução de ácido sulfúrico de concentração 18mol/L, é igual a:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">0,50 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">2,00 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-bidi-font-weight: bold;">2,25 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold;">4,50 L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l6 level1 lfo5; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-bidi-font-weight: bold;">9,00 L.</span></div>
<div class="MsoBodyTextIndent" style="margin: 0cm 0cm 0pt;">
<br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">7) O volume de água, em mL, que deve ser adicionado a 80 mL de solução aquosa 0,1 mol/L de uréia, para<span style="mso-spacerun: yes;"> </span>que a solução resultante seja 0,008 mol/L, deve ser igual a:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">800</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1000</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> 9</span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">20</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">80</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">100</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 39pt; mso-list: l2 level1 lfo7; tab-stops: list 39.0pt; text-align: justify; text-indent: -17.7pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<br /></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">8) Que volume de água deve-se adicionar a 400 mL de solução 367,5g/L de ácido sulfúrico, para que se torne 122,5g/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">800 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">1000 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">1800 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">200 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1200 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 40.2pt; mso-list: l7 level1 lfo1; tab-stops: list 40.2pt; text-align: justify; text-indent: -18pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt; text-align: justify;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">9) Quantos cm<sup>3</sup> de H<sub>2</sub>O temos que adicionar a 1,50 litro de solução 0,50 mol/L, a fim de torná-la 0,20 mol/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1500</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">2250</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1000</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> 3</span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">750</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">500<span style="mso-spacerun: yes;"> </span></span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 42pt; mso-list: l1 level1 lfo2; tab-stops: list 42.0pt; text-align: justify; text-indent: -18pt;">
</div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">10) Que volume de água destilada devemos adicionar a 100mL de solução 0,5 mol?l de ácido sulfúrico para que ela se torne 0,1 mol/L?</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">100 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">400 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">500 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">550 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1000 mL</span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">.</span><br />
<br />
<br />
<h1 style="margin: 0cm 0cm 0pt;">
<span style="color: navy; font-family: "Arial","sans-serif"; font-size: 10pt;">MISTURA DE SOLUÇÕES DE MESMO SOLUTO<o:p></o:p></span></h1>
</div>
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">1)Qual a molaridade de uma solução de NaOH formada pela mistura de 100 mL de solução 5 mol/L com<span style="mso-spacerun: yes;"> </span>300 mL de solução 2 mol/L, da mesma base ?</span><br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36.6pt; mso-list: l1 level1 lfo2; tab-stops: list 36.6pt; text-align: justify; text-indent: -15.3pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">1,15 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36.6pt; mso-list: l1 level1 lfo2; tab-stops: list 36.6pt; text-align: justify; text-indent: -15.3pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">2,50 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36.6pt; mso-list: l1 level1 lfo2; tab-stops: list 36.6pt; text-align: justify; text-indent: -15.3pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">2,75 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36.6pt; mso-list: l1 level1 lfo2; tab-stops: list 36.6pt; text-align: justify; text-indent: -15.3pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">3,55 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36.6pt; mso-list: l1 level1 lfo2; tab-stops: list 36.6pt; text-align: justify; text-indent: -15.3pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">5,00 mol/L.</span></div>
<br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">2)O volume de uma solução de hidróxido de sódio 1,5 mol/L que deve ser misturado a 300 mL de uma solução 2 mol/L da mesma base, a fim de torná-la solução 1,7 mol/L é:</span><br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l2 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">200 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l2 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">20 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l2 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">2000 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l2 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">450 mL.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l2 level1 lfo3; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">350 mL.<o:p></o:p></span></div>
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;"></span><br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">3)Qual a molaridade de uma solução de ácido sulfúrico (H2SO4) obtida pela mistura de 30 mL do ácido 1,3%, densidade de 1,5 g/mL e 40 mL do mesmo ácido 0,5 mol/L ?</span><br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 18pt; text-align: justify;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;"><span style="mso-spacerun: yes;"> </span>Dados: H = 1 u.; O = 16 u.; S = 32 u</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,64 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,32 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,37 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,10 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,98 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo4; tab-stops: list 36.0pt; text-align: justify; text-indent: -18pt;">
</div>
<div class="MsoBodyText" style="margin: 0cm 0cm 0pt 21.3pt; text-indent: -21.3pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">4) 200 mL de uma solução aquosa de glicose de concentração 60g /L foram misturados a 300 mL de uma solução de glicose de concentração 120g /L. A concentração da solução final, em g/L, será:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo1; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">96 g/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo1; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">9,6 g/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo1; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">90 g/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo1; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="EN-US" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: EN-US;">180 g/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l3 level1 lfo1; tab-stops: list 36.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">60 g/L.<span style="mso-spacerun: yes;"> </span></span><br />
<br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">5) Duas amostras de soluções aquosas de NaOH, uma de volume 200 mL e 0,15 mol/L e a outra de volume 100 mL e 0,30 mol/L, foram misturadas. A molaridade da solução final será:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 54.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,100 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 54.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,150 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 54.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,200 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 54.0pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,225 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 54.0pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,450 mol/L.<o:p></o:p></span></div>
<br />
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 21.3pt; text-align: justify; text-indent: -21.3pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;">6) 30 mL de solução 1,0 mol/L de HNO<sub>3</sub> foram adicionados a 20 mL de solução 0,2 mol/L do mesmo ácido. A molaridade da solução resultante é:</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">1,2 mol / L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,12 mol / L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,68 mol / L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,07 mol / L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 36pt; mso-list: l0 level1 lfo1; tab-stops: list 36.0pt 42.55pt; text-align: justify; text-indent: -14.7pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,14 mol / L.<o:p></o:p></span></div>
<br />
<div class="MsoBodyText2" style="line-height: normal; margin: 0cm 0cm 0pt 21.3pt; text-indent: -21.3pt;">
<span style="font-size: x-small;"><span style="font-family: Arial;">7) Considere as seguintes soluções: 250 mL de solução de KOH, de concentração 0,20 mol/L<span style="mso-spacerun: yes;"> </span>e<span style="mso-spacerun: yes;"> </span>167 mL de solução da mesma base, de concentração 0,40 mol/L. A concentração, em mol/L, da solução obtida pela mistura das duas soluções é igual a:</span></span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 46.5pt; mso-list: l0 level1 lfo1; tab-stops: list 39.75pt 46.5pt; text-align: justify; text-indent: -25.2pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">a)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,60 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 46.5pt; mso-list: l0 level1 lfo1; tab-stops: list 39.75pt 46.5pt; text-align: justify; text-indent: -25.2pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">b)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,35 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 46.5pt; mso-list: l0 level1 lfo1; tab-stops: list 39.75pt 46.5pt; text-align: justify; text-indent: -25.2pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">c)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,30 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 46.5pt; mso-list: l0 level1 lfo1; tab-stops: list 39.75pt 46.5pt; text-align: justify; text-indent: -25.2pt;">
<span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">d)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span lang="ES-TRAD" style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-ansi-language: ES-TRAD;">0,28 mol/L.</span></div>
<div class="MsoNormal" style="margin: 0cm 0cm 0pt 46.5pt; mso-list: l0 level1 lfo1; tab-stops: list 39.75pt 46.5pt; text-align: justify; text-indent: -25.2pt;">
<span style="font-family: "Arial","sans-serif"; font-size: 10pt; mso-fareast-font-family: Arial;"><span style="mso-list: Ignore;">e)<span style="font-size-adjust: none; font-stretch: normal; font: 7pt/normal "Times New Roman";"> </span></span></span><span style="font-family: "Arial","sans-serif"; font-size: 10pt;">0,20 mol/L.<o:p></o:p></span><br />
<span style="font-family: "Arial","sans-serif"; font-size: 10pt;"><br /></span>
<span style="color: red; font-family: "Arial","sans-serif";"><b>GABARITO</b></span><br />
<span style="color: red; font-family: "Arial","sans-serif";"><b><br /></b></span>
<span style="color: lime; font-family: "Arial","sans-serif";"><b>DILUIÇÃO</b></span><br />
<span style="color: lime; font-family: "Arial","sans-serif";"><b><br /></b></span>
<span style="font-family: Arial, sans-serif;">1) 0,01mol/L 2) 0,2mol/L 3) 0,48 mol/L 4) 2.10 <span style="font-size: xx-small;">-2 </span>mol/L 5) 0,002 mol/L</span><br />
<span style="font-family: Arial, sans-serif;">6) 2,25 L 7) 920 mL 8) 800 mL 9) 2250 cm<span style="font-size: xx-small;">3 </span> 10) 400 mL</span><br />
<span style="font-family: Arial, sans-serif;"><br /></span>
<span style="color: #660000; font-family: Arial, sans-serif;"><b>MISTURA </b></span><br />
<span style="color: #660000; font-family: Arial, sans-serif;"><b><br /></b></span>
<span style="font-family: Arial, sans-serif;">1) 2,75 mol/L 2) 450 mL 3) 0,37 mol/L 4) 96 g/L 5) </span><span style="font-family: Arial, sans-serif;">0,2</span><span style="font-family: Arial, sans-serif;"> </span><span style="font-family: Arial, sans-serif;"> mol/L</span><br />
<span style="font-family: Arial, sans-serif;">6) </span><span style="font-family: Arial, sans-serif;">0,68</span><span style="font-family: Arial, sans-serif;">mol/L 7) 0,28 mol/L</span></div>
Prof Sergivaldohttp://www.blogger.com/profile/17651704588752856435noreply@blogger.com2